Item 12 a student mixes 40. Ml of 0. 10mhbr(aq) with 60. Ml. The [oh−] of the resulting solution is 0.02.
A solution is a mixture of two or more than two substances.
The reaction is [tex]\rm HBr + KOH = KBr + H_2O[/tex]
To calculate the OH-
1 mole of HBr reacts with 1 mole of KOH
Moles of HBr = 40 mL × 0.1 M = 4 mm moles
Moles of KOH = 60 mL × 0.1 M = 6 m moles
Moles of [OH-] = 6 - 4 = 2 m moles
Volume of solution = 100 mL
[OH-] = 2mmoles/100 mL = 0.02 M
Thus, the [oh−] of the resulting solution is 0.02.
Learn more about OH ions.
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