At a playground, a 22 kg child plays on a slide that drops through a height of 2.4 m . the child starts at rest at the top of the slide. on the way down, the slide does a nonconservative work of -366 j on the child. part a what is the child's speed at the bottom of the slide

Respuesta :

The child's speed at the bottom of the slide is determined from conservation of energy as 3.71 m/s.

Speed of the child at the bottom of the slide

The speed of the child is determined from the principle of conservation of mechanical energy.

K.E + Ef = P.E

were;

  • Ef is the energy lost to friction

Solve for kinetic energy

K.E + 366 = mgh

K.E = mgh - 366

K.E = (22 x 2.4 x 9.8) - 366

K.E = 151.44 J

Now solve for speed

K.E = ¹/₂mv²

2K.E = mv²

v² = 2K.E/m

v² = (2 x 151.44)/(22)

v² = 13.77

v = 3.71 m/s.

Learn more about conservation of energy here: https://brainly.com/question/166559

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