There are sufficient evidences which are of 5% significance level to reject the claim.
A statistical test used to compare observed results with expected results is referred to as the chi-square test.
According to the given scenario,
To calculate:
Evidence to make conclusion to the geneticist's claim.
Total fruits = 1 + 3 + 3 + 9 = 16
As per the expected number of fruit flies
Each species = 1/16(2000) = 125.3/16(2000) = 375.3/16(2000) = 375.9/16(2000)
Each species = 1125
According to Chi-Square test -
[tex]X^{2} =\epsilon\frac{(O_{i}-E_{i})^{2} }{E_{i}}[/tex]
[tex]X^{2}[/tex] = ( 110 - 125)²/125 + ( 345 - 375)²/375 + ( 360 - 375)²/375 + ( 1185 - 1125)²/1125
[tex]X^{2}[/tex] = (15)²/125 + (30)²/375 + (15)²/375 + (60)²/1125
[tex]X^{2}[/tex] = 8
with df = 4 - 1 = 3, and P( x² > 8) = 0.0460.
Thus, with a P-value, it is small, indicates 5% significance level to reject the claim.
For more details regarding the chi-square test, visit:
https://brainly.com/question/14082240
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