Answer:
[tex]x=-6; y=4[/tex]
Step-by-step explanation:
Step 0: retwite the second equation by dividing LHS and RHS by 3.
[tex]x+2y=2[/tex]
Step 1: combine them as the first minus twice the second to eliminate y
[tex]I - 2\times II : 5x+4y -2x-4y=-14-4 \rightarrow 3x=-18 \rightarrow x= -6[/tex]
Step 2a: At this point I would replace the value of x in the second equation to easily solve for y. That will give you [tex]-6+2y=2 \rightarrow y=4[/tex]. I do imagine you're required to use the same method to solve for y even if it's slower so...
Step 2b: Combine them again, taking the first minus 5 times the second to eliminate x:
[tex]I-5II: 5x+4y-5x-10y=-14-10 \rightarrow -6y=-24 \rightarrow y=4[/tex]
