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A dog runs out the door and through the neighborhood. It starts at point A and ends up at point F. What is its displacement at F? D C A 5 OA. 5 km east and 4 km north B. 2 km east and 5 km north OC. 11 km east and 4 km north D. 7 km east and 2 km north​

A dog runs out the door and through the neighborhood It starts at point A and ends up at point F What is its displacement at F D C A 5 OA 5 km east and 4 km nor class=

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onyebuchinnaji

The displacement of the dog can summarized as 4 km north and 5 km east with a resultant magnitude of 6.4 km.

Displacement of the dog

The displacement of the dog is the change in the position of the dog from the initial position to the final position.

The displacement is the straight line from point A to point F.

  • Vertical length, A - E = 4 km
  • Horizontal length, A - F = 5 km

Straight line from A to F is calculated as follows;

r = √(4² + 5²)

r = 6.4 km

Thus, the displacement of the dog can summarized as 4 km north and 5 km east with a resultant magnitude of 6.4 km.

Learn more about displacement here: https://brainly.com/question/2109763

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