The temperature of the given amount of oxygen gas with the given volume and pressure is 433K.
The Ideal gas law or general gas equation emphasizes on the state or behavior of a hypothetical ideal gas. It states that "the pressure multiplied by volume is equal to moles multiply by the universal gas constant multiply by temperature.
It is expressed as;
PV = nRT
Where P is pressure, V is volume, n is the amount of substance, T is temperature and R is the ideal gas constant ( 0.08206 Latm/molK )
Given the data in the question;
PV = nRT
PV = nRT
T = PV / nR
T = ( 3.55292atm × 25L ) / ( 2.5mol × 0.08206 Latm/molK)
T = 88.823Latm / 0.20515Latm/molK
T = 433K
Therefore, the temperature of the given amount of oxygen gas with the given volume and pressure is 433K.
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