Respuesta :

The standard form is given by(As highest degree is 2 we will take till degree 2 i.e quadratic)

  • ax²+bx+c

So

#1

  • 1/2x-1/4
  • 0x²+1/2x-1/4

Multiply 4

  • 0x²+2x-1

Here

  • a=0
  • b=2
  • c=-1

#2

  • 5x²-2x+6

Already in standard form

  • a=5
  • b=-2
  • c=6
semsee45

Answer:

[tex]\dfrac{5}{2}x^3-\dfrac{9}{4}x^2+\dfrac{7}{2}x-\dfrac{3}{2}[/tex]

Step-by-step explanation:

The product of the two expressions is:

[tex]\left(\dfrac{1}{2}x-\dfrac{1}{4}\right)(5x^2-2x+6)[/tex]

[tex]=\dfrac{1}{2}x(5x^2-2x+6)-\dfrac{1}{4}(5x^2-2x+6)[/tex]

[tex]=\dfrac{5}{2}x^3-\dfrac{2}{2}x^2+\dfrac{6}{2}x-\dfrac{5}{4}x^2+\dfrac{2}{4}x-\dfrac{6}{4}[/tex]

[tex]=\dfrac{5}{2}x^3-x^2-\dfrac{5}{4}x^2+3x+\dfrac{1}{2}x-\dfrac{3}{2}[/tex]

[tex]=\dfrac{5}{2}x^3-\dfrac{9}{4}x^2+\dfrac{7}{2}x-\dfrac{3}{2}[/tex]

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