mavivian
contestada

A rocket is launched from atop a 101 foot cliff with an initial velocity of 116 feet per second. After how many seconds will the rocket land? Round to the nearest second.

Respuesta :

Answer:

8 seconds

Step-by-step explanation:

Assuming a vertical launch, the position of the rocket is given by

 xf = xo + vo t + 1/2 at^2

      xo = 101   ft   vo = 116   xf = 0 (when it hits the ground)   a = -32.2 ft/s^2

0 = 101 + 116 t - 16.1 t^2     Use Quadratic Formula to find t = ~~ 8 sec

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