1.25L volume of oxygen gas at 320 K and 680 torr will react completely with 25 L of NO gas at the same temperature and pressure.
The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
It is given that P= 680 torr = 0.895 atm
R=0.0821 Latm K⁻¹mol⁻¹
PV= nRT
0.895 * 2.5 = n * 0.0821 * 320
n = 0.0851 mol NO
From the reaction Stoichiometry we can see that for 2 moles of NO 1 mole of Oxygen is used
so for 0.0851 moles of NO, number of moles of oxygen will be used
Moles of Oxygen =
1 mole of Oxygen *0.0851 moles of NO/2 moles of NO
=0.0425 moles of O₂
Using Ideal Gas Law
At 0.895 atm volume of oxygen used can be calculated as follows
0.895 * V = 0.0425 * 0.0821*320
V= 1.25L of O₂
Therefore 1.25L volume of oxygen gas at 320 K and 680 torr will react completely with 25 L of NO gas at the same temperature and pressure.
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