Answer:
Y = 5 sin(2x) + 4
The amplitude of the sin itself is 1 .
The amplitude of 5sin is 5 .
Every time the "argument" of the sin increases by 2π
another period starts.
The first period goes from zero until 2x = 2π .
So the length of the period is π .
The phase shift is the value of the angle when x=0.
That's zero.
The sin itself wiggles up and down, regularly and symmetrically,
above and below the x-axis (y=0). In this equation, the whole thing
is shifted up 4 units by that +4 on the end, so it's wiggling up and down
above and below the line y=4. The vertical shift is +4 .
If this function were an electrical signal, we would say that its
period is π seconds, its frequency is 1/π Hz, and it has an
AC amplitude of 5 riding on a DC component of 4 .
Step-by-step explanation:
