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At a fundraiser, a participant is asked to guess what is inside an unlabeled can for a possible prize. if there are two crates of cans to choose from, each having a mixture of vegetables and soup, what is the probability that the first participant will select a vegetable can from the left crate given each situation?


a. the left crate has 2 cans of vegetables and 8 cans of soup, and the right crate has 7 cans of vegetables and 3 cans of soup.


b. the left crate has 8 cans of vegetables and 2 cans of soup, and the right crate has 5 cans of vegetables and 5 cans of soup.

Respuesta :

Probability helps us to know the chances of an event occurring. The probability that the first participant will select a vegetable can from the left crate is 0.615.

What is Probability?

Probability helps us to know the chances of an event occurring.

[tex]\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}[/tex]

A.) The probability that the first participant will select a vegetable can from the left crate will be,

[tex]\rm Probability = \dfrac{\frac{1}{2} \times \frac{2}{10}}{(\frac{1}{2} \times \frac{2}{10})+(\frac{1}{2}\times \frac{7}{10})}\\\\\\Probability = \dfrac{0.1}{0.1+0.35} = 0.222[/tex]

Hence, the probability that the first participant will select a vegetable can from the left crate is 0.222.

B.) The probability that the first participant will select a vegetable can from the left crate will be,

[tex]\rm Probability = \dfrac{\frac{1}{2} \times \frac{8}{10}}{(\frac{1}{2} \times \frac{8}{10})+(\frac{1}{2}\times \frac{5}{10})}\\\\\\Probability = \dfrac{0.4}{0.4+0.25} = 0.615[/tex]

Hence, the probability that the first participant will select a vegetable can from the left crate is 0.615.

Learn more about Probability:

https://brainly.com/question/795909

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