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The f(x) is a parent function and applying the transformation it shifted upside by 2 units and shifted left side by 7 units.
It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
We have two functions:
[tex]\rm f(x) = \dfrac{1}{x-3}+1[/tex] and
[tex]\rm g(x) = \dfrac{1}{x+4}+3[/tex]
f(x) is a parent function:
First transformation:
Add 2 to the f(x)
f(x) will shift upside by 2 units
[tex]\rm f(x) = \dfrac{1}{x-3}+1+2\\\\\rm f'(x) = \dfrac{1}{x-3}+3[/tex]
Second transformation:
(x) → (x+7)
[tex]\rm g(x) = \dfrac{1}{x+7-3}+3[/tex]
[tex]\rm g(x) = \dfrac{1}{x+4}+3[/tex]
The function will shift left side by 7 units.
Thus, the f(x) is a parent function and applying the transformation it shifted upside by 2 units and shifted left side by 7 units.
Learn more about the function here:
brainly.com/question/5245372
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