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There are 0.45 moles of Kr gas at a pressure of 1.35 atm and a temperature of 35°C. What volume would this gas occupy? (R= 0.0821 Mh/*))

Respuesta :

Apply ideal gas equation

  • PV=nRT
  • V=nRT/P
  • V=0.45(0.0821)(273+35)/1.35
  • V=0.45(0.0821)(308)/1.35
  • V=8.42L

Use ideal gas equation

  • PV=nRT
  • 1.35V=0.45(308)(0.0821)
  • 135V=11.379
  • V=8.4L

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