Answer:
Center is [tex](8,-1)[/tex]
Radius is [tex]3[/tex]
Step-by-step explanation:
To convert from a general form equation to a standard form equation, we must complete the square for each variable to simplify. Make sure to rearrange the equation to complete the square more easily:
[tex]x^2+y^2-16x+2y+56=0\\\\x^2-16x+56+y^2+2y=0\\\\x^2-16x+56(+8)+y^2+2y(+1)=0+8+1\\\\x^2-16x+64+y^2+2y+1=9\\\\(x^2-16x+64)+(y^2+2y+1)=9\\\\(x-8)^2+(y+1)^2=9[/tex]
Since the equation of a circle is [tex](x-h)^2+(y-k)^2=r^2[/tex], our circle will have a center of [tex](h,k)\rightarrow(8,-1)[/tex] and a radius of [tex]r^2=9\rightarrow r=3[/tex].
