The energy stored in the capacitor at given capacitance and voltage is determined as 396.5 J.
The energy stored in the capacitor is calculated as follows;
E = ¹/₂CV²
where;
V is the voltage
E = ¹/₂ x 13 x 10⁻⁶ x (7.81 x 10³)²
E = ¹/₂ x 13 x 10⁻⁶ x (7.81 x 10³)²
E = 396.5 J
Thus, the energy stored in the capacitor at given capacitance and voltage is determined as 396.5 J.
The complete question is below
An electronic defibrillator used on heart attack victims works by delivering charge stored in a capacitor. If the device utilizes a 13.0 μF capacitor charged to 7.81 × 103 V, what is the energy stored in the capacitor?
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