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WILL MARK BRAINLIEST (if theres more than one answer)!!!!

If 28.0g MgCO3 reacts with excess H2SO4, what mass of water is produced?
a) 18.0g H2O
b) 24.0g H2O
c) 6.00g H2O
d) 12.0g H2O

THANK YOU <333

Respuesta :

TheDoctorOfStone

Answer:

First you have to predict and balance the equation between MgCO3 and H2SO4

MgCO3 + H2SO4 -> MgSO4 + CO2 + H2O

Now you have to find the moles of MgCO3 by dividing the mass you have (28.0g) by the molar mass of Magnesium Carbonate (84.31g/mol)

28.0/84.31 = 0.332 mol

We know that the mol to mol ratio of Magnesium carbonate to Water is 1:1 because the coefficients for the balanced equation is 1:1, so to get the mass of water, multiply the mol you have (0.332 mol) by the molar mass of water (18.01g/mol)

0.332 x 18.01 = 5.97g of H2O

round 5.97 g to 6g of H2O

The answer is (C), 6.00g of H2O

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