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A frog jumps in the air. The height, in inches of the frog is modeled by the function h(t) = 60t-75t^2, where t is the time after it jumped, measured in seconds.
Solve 60-75² = 0. What do the solutions tell us about the jumping frog?​

Respuesta :

The solution of the equation tells that at t = 0 seconds frogs will start to jump and after t = 0.8 seconds the frog will come onto the ground.

What is a parabola?

It is defined as the graph of a quadratic function that has something bowl-shaped.

We have a parabolic equation that represents height, in inches of the frog is modeled by the function:

h(t) = 60t - 75t²

h(t) = 0

60t - 75t² = 0

t(60 - 75t) = 0

t = 0 or t = 60/75 = 0.8 seconds

Thus, the solution of the equation tells that at t = 0 seconds frogs will start to jump and after t = 0.8 seconds the frog will come onto the ground.

Learn more about the parabola here:

brainly.com/question/8708520

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