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An ice fisherman removes an 8-kg block of ice from a local pond he plans to use for fishing. The block is at rest on the surface of the pond when a 70-kg sledder moving at a speed of 22 m/s collides with the brick of ice. After the collision, the sledder and the block of ice move forward as one. Calculate the final speed that they are travelling at.

Velocity: _ m/s

Respuesta :

Eduard22sly

The final velocity that the 8 Kg block of ice and the 70 Kg sledder are traveling at is 19.74 m/s

Data obtained from the question

  • Mass of block (m₁) = 8 Kg
  • Velocity of block (v₁) = 0 m/s
  • Mass of sledder (m₂) = 70 Kg
  • Velocity of sledder (v₂) = 22 m/s
  • Final velocity (v) =?

How to determine the final velocity

v = (m₁v₁ + m₂v₂) / (m₁ + m₂)

v = [(8 × 0) + (70 × 22)] / (8 + 70)

v = [(0 + 1540)] / 78

v = 1540 / 78

v = 19.74 m/s

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