The energy of the photons will be 3.013 ×10 ⁻¹⁸ eV, Debroglie equation is employed in the given problem.
What is the energy of a photon?
The energy carried by a single photon is referred to as photon energy. The photon's electromagnetic frequency is directly proportional to the amount of energy.
The given data in the problem will be;
λ is the wavelength of electromagnetic radiation=412 nm=412×10⁻⁹m
c is the speed of light=3×10⁸ m/
E is the energy of photons=?
We use the equation to calculate the energy of a single photon of electromagnetic radiation.
[tex]\rm E= h \dfrac{c}{\lambda} \\\\ E=6.63 \times 10^{-34}\ J s.\times \frac{3 \times 10^8 }{412 \times 10^{-9}} \\\\ E = 4..8 \times 10^{-37} J\\\\E=3.013 \times 10^{-18} \ eV[/tex]
Hence, the energy will be 3.013 ×10 ⁻¹⁸ eV,
To learn more about the energy of photons, refer to the link;
https://brainly.com/question/19795551
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