1, 5, 12, 14, 29, 45, 48, 61, 72, 84, 96
Interquartile range ( IQR )
First, find the median of 2 halves.
1, 5, 12, 14, 29, 45, 48, 61, 72, 84, 96
[tex]q_{3} = 72[/tex]
[tex]q_{1} = 12[/tex]
Then, find the difference
[tex] = q_{3} - q_{1}[/tex]
[tex] = 72 - 12[/tex]
[tex]\large\boxed{\sf{IQR=60}}[/tex]
There for the interquartile range of the given data set is 60
Answer= Option A