Answer:
14.50 feet (approx) is the distance,that the box has to travel to move from point A to point C.
Step-by-step explanation:
Distance = ?
Here in the given right triangle we will use sin's formulae,
[tex] \rm \: sin \theta = \cfrac{adjacent}{hypotenuse} [/tex]
- Sin ∅ = sin*65°
- Adjacent = 12 ft
- Let Hypotenuse be x.
Then,
- [tex] \sin \: 65 = \cfrac{12}{x} [/tex]
Solving for x,
- [tex]x \times \sin65 = 12[/tex]
- [tex]x = \cfrac{12}{sin65} [/tex]
- [tex]x = \cfrac{12}{0.826829} [/tex]
- [tex] \boxed{ \rm \: Hypotenuse = 14.5132 \approx14.50 \: \rm feet}[/tex]
We can conclude that:
14.50 feet (approx) is the distance,that the box has to travel to move from point A to point C.
