The area of the figure is 169.1.Given the figure attached has composed of a parallelogram of sides 8 and 24 and the semicircle has diameter of 8.
Now, Area of semicircle will be,
[tex]A = (\pi \: r {}^{2} ) \\ 2 [/tex]
Here diameter of semicircle is 8 so its radius will be half of it, means radius is
[tex]So, A = \pi(4) ^{2} \\ - - \\ 2[/tex]
[tex]a = \pi \times 8 \\ [/tex]
A = 25.132
Figure will be
(144+25.132= 169.132),
on rounding it to nearest tenth place we get Area is 169.1.
Hence the area of the figure is 169.1.
