Find the magnitude of the induced current that flows through the resistor shown in the figure at t=3 s, if the magnetic field through the wire loop of 3.0 cm radius changing with time according to this equation B=2t^2−3.

Respuesta :

The magnitude of the induced current is, (I=9 /R). The principal of ohm's law is employed in the given problem.

What is induced emf?

Emf is the production of a potential difference in a coil as a result of changes in the magnetic flux passing through it.

When the flux coupling with a conductor or coil changes, electromotive force, or EMF, is said to be induced.

The given data in the problem is;

B is the magnetic field,= 2t^2−3.

t(time)=3 sec

The induced EMF is found as;

[tex]\rm E= \frac{d \phi}{dt} \\\\\ \rm E= \frac{d(2t^2-3)}{dt} \\\\\ E=4t-3\\\\\ t= 3 sec \\\\ E=12-3 \\\\\ E= 9 \ V[/tex]

From ohm's law;

E=IR

I=E/R

I=9 /R

Hence,the magnitude of the induced current is, (I=9 /R).

To learn more about the induced emf, refer to the link;

https://brainly.com/question/16764848

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