At 0.500 atm and 15.0°C a sample of gas occupies 120. L. What volume does it occupy at
0.250 atm and 10.0°C?

O236 L
O 60 L
O 111 L
O 480 L

Respuesta :

The combined gas law is used to determine the relationship between the pressure, temperature, and volume of the gas. The volume of the gas at 0.250 atm is 236 L. Thus, option A is correct.

What is combined gas law?

The combined gas law uses the ideal gas equation to estimate the temperature, volume, or pressure of the given gas.

Given,

Initial pressure = 0.500 atm

Initial temperature = 288.15 K

Initial volume = 120 L

Final pressure = 0.250 atm

Final temperature = 283.15 K

The final volume is calculated as:

V₂ =  (P₁V₁ T₂) ÷ (P₂ T₁)

= 0.500 × 120 × 283.15 ÷ 0.250 × 288.15

= 16989 ÷ 72.03

= 235.86 L

Therefore, 236 L is the final volume at 0.250 atm.

Learn more about combined gas law here:

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