Under the assumption of uniform iron beam and definition of uniform density, the total mass of the iron beam is equal to 81931.2 grams.
Let suppose that the iron beam has an uniform density, the mass of the iron beam (m), in gram, is equal to the product of its density (ρ), in grams per cubic centimeter, and its volume (V), in cubic centimeters:
m = ρ · V (1)
If we know that ρ = 10504 cm³ and V = 7.8 g/cm³, then the mass of the iron beam is:
m = (7.8 g/cm³) · (10504 cm³)
m = 81931.2 g
Under the assumption of uniform iron beam and definition of uniform density, the total mass of the iron beam is equal to 81931.2 grams.
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