The set of equation that models the point of intersection of the arrow
and the target is: y = -0.002x² +0.25x + 6 and y = 0.15x.
Set of equation that models the point of intersection
Given parameters:
Point of intersection of the line and the parabola=(85.21,12.78)
Hence:
First set
y = -0.002 × 48.67² + 0.25 × 85.21 + 6= 12.78
Linear function y ≠ x
Third set
y = -0.002 × 85.21² + 0.25 × 85.21+ 6= 12.78
y = C·x
12.78 = 85.21·x
C=12.78/85.21
C=0.149
C=0.15 (Approximately)
Hence:
y=0.15x
Therefore the set of equation that models the point of intersection of the arrow and the target is: y = -0.002x² +0.25x + 6 and y = 0.15x.
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