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A test charge is placed at a distance of 2.0 × 10-1 meters from a charge of 5.4 × 10-8 coulombs. what is the electric field at the test charge? (k = 9.0 × 109 newton·meter2/coulomb2) a. 1.0 × 10-2 newtons/coulomb b. 1.2 × 104 newtons/coulomb c. 2.5 × 104 newtons/coulomb d. 3.5 × 10-1 newtons/coulomb e. 5.4 × 10-8 newtons/coulomb

Respuesta :

onyebuchinnaji

The electric field at the test charge is determined as 1.2 x 10⁴ Newtons/coulomb.

Electric field at the test charge

The electric field at the test charge is calculated as follows;

E = F/q

E = (kq/r²)

where;

  • k is Coulomb's constant
  • q is charge
  • r is distance of separation

E = (9 x 10⁹ x 5.4 x 10⁻⁸)/(0.2)²

E = 1.2 x 10⁴ N/C

Thus, the electric field at the test charge is determined as 1.2 x 10⁴ Newtons/coulomb.

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