The median of the number recorded in the question is 51.5 feet. This is obtained by dividing the sum of two numbers that occur centrally in half.
The central value in a list ordered from smallest to largest is the median of a set of values.
The formula for the Inter-quartile range is given as:
IQR = Q₃- Q₁ (that is Median of the Upper Half Less the Median of the lower half)
Step 1 - First, let's arrange the numbers sequentially
→ 40, 40, 47, 49, 50, 53, 55, 57, 63, 76
Step 2 - Determine the upper and lower halves and their median
If the Lower half is 40, 40, 47, 49, 50, then it's median is 47
If the Upper half is 53, 55, 57, 63, 76, then its median is 57.
Hence:
IQR = 57 - 47
= 10 feet.
No, the friends didn't perform better in the second round because the was a significant drop in the median and the IQR. The median dropped from 51.5 to 47 and the IQR from 10 to 6.
It can be concluded that the distance in the second set of data is less variable when juxtaposed with those form the first set.
Learn more about Median at:
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