Respuesta :

The five consecutive even integers such that the four times the first number plus the fourth number is 35 are 6 , 8, 10, 12, and 14.

How to find the consecutive integers of the sequence?

The even integers are consecutive. Therefore,

let the first even integer = x

Therefore, the sequence is as follows:

x, x + 2, x + 4, x + 6, x + 8.....

Therefore,

4x + x + 6 = 36

5x + 6 = 36

5x  = 36 - 6

5x = 30

x = 30 / 5

x = 6

Therefore, the numbers are as follows;

  • 6
  • 6 + 2 = 8
  • 6 + 4 = 10
  • 6 + 6 = 12
  • 6 + 8 = 14

learn more on integers here:https://brainly.com/question/15381903

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