The following two-way table shows the distribution of pets in a large apartment building. A 4-column table with 3 rows titled Pets. Column 1 has entries cat, no cat, total. Column 2 is labeled dog with entries 27, 3, 30. Column 3 is labeled no dog with entries 25, 45, 70. Column 4 is labeled Total with entries 52, 48, 100. Suppose we select a resident of the apartment building at random. Let event A = Cat and event B = Dog. Calculate and interpret P(A|B). The probability that a randomly selected resident owns a , given that the person also owns a , is equal to approximately .

Respuesta :

The way you have to do it is by Shaka

Answer:

The probability that a randomly selected resident owns a

✔ cat

, given that the person also owns a

✔ dog

, is equal to approximately

✔ 0.90

.

Step-by-step explanation:

Just did it on edge.

Next slide answer is:

The probability that a randomly selected resident owns a

✔ dog

, given that the person also owns a

✔ cat

, is equal to approximately

✔ 0.519

.