The equation for the path of a launched projectile contains the vertex (5, 120) and the point (25, 80) on the boundary is shown in the graph.
It is defined as the graph of a quadratic function that has something bowl-shaped.
The path of the launched projectile will a parabola.
We have the vertex of the parabola (5, 120)
The standard equation in terms of vertex (h, k)
[tex]\rm y = a(x-h)^2+k[/tex]
Plug the points:
[tex]\rm y = a(x-5)^2+120[/tex]
To find the value of “a” plug point (25, 80)
[tex]\rm 80 = a(25-5)^2+120[/tex]
a = -1/10
Plug this into the equation;
The path of the equation:
[tex]\rm y = \dfrac{-1}{10}(x-5)^2+120[/tex]
Thus, the equation for the path of a launched projectile contains the vertex (5, 120) and the point (25, 80) on the boundary is shown in the graph.
Learn more about the parabola here:
brainly.com/question/8708520
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