Answer:
0.956 grams O₂ or
0.956 milliliters O₂ or
9.56 x 10⁻⁴ L O₂
Explanation:
If the reactant were to decompose completely, the entire balanced reaction would look like this:
2 KClO₃ --> 2 K(s) + Cl₂(g) + 3 O₂(g)
To find the answer, (1) convert the grams of KClO₃ to moles (via molar mass from periodic table), then (2) convert moles KClO₃ to moles O₂ (via mole-to-mole ratio from balanced equation), then (3) convert moles O₂ to grams (via molar mass from periodic table).
Molar Mass (KClO₃) = 39.098 g/mol + 35.453 g/mol + 3(15.999) g/mol
Molar Mass (KClO₃) = 122.548 g/mol
Molar Mass (O₂) = 2(15.999) g/mol
Molar Mass (O₂) = 31.998 g/mol
2.44 g KClO₃ 1 mole KClO₃ 3 moles O₂ 31.998 g
-------------------- x -------------------------- x -------------------- x ------------------------
122.548 g 2 moles KClO₃ 1 mole O₂
= 0.956 grams O₂
= 0.956 milliliters O₂
= 9.56 x 10⁻⁴ L O₂
**The prompt askes to determine the volume. As far as I know, there is no easy way to find liters/milliliters with the given information. As such, I found the mass of O₂ instead. Technically, grams is equal to milliliters, so this may be what you are looking for. Then, you can convert from milliliters to liters by dividing by 1,000 (if necessary). **
