Respuesta :

Answer:

Yes, by ASA congruence.

Step-by-step explanation:

Solving :

  • ∠DAB = ∠BCD  (indicated in diagram)
  • ∠ADB = ∠DBC (indicated in diagram)
  • BD = BD (common side)
  • ΔABD ≅ ΔCDB

Hence, as 2 angles and a side of the triangles are equal, we can say they are congruent by ASA congruence.

Ver imagen Аноним

[tex]\huge\underline{{\sf Answer}}[/tex]

[tex] \textbf{Let's check if the two triangles are } [/tex][tex] \textbf{congruent} [/tex] ~

[tex] \large\textsf{Given information } [/tex]:

[tex] \textsf{Two angles of a triangle is equal to corresponding} [/tex] [tex] \textsf{two angles of another triangle, and they} [/tex][tex] \textsf{have one side in common (should be equal} [/tex][tex] \textsf{for both) } [/tex]

[tex] \textsf{So, after analyzing this information, we can } [/tex][tex] \textsf{conclude that the two triangles are congruent by} [/tex][tex] \textsf{AAS congruency criteria.} [/tex]

[tex] \texttt{[ since two angles are equal and one} [/tex][tex] \texttt{non included side is common/equal ]} [/tex]