Answer:
Rearrange both inequalities to make y the subject.
Momentarily swap the inequality sign for an equals sign in order to calculate two points for each line.
Inequality 1
[tex]2y \leq x-10[/tex]
[tex]\implies y < \dfrac{1}{2}x-5[/tex]
[tex]x=0\implies y=\dfrac{1}{2}(0)-5 \implies (0,-5)[/tex]
[tex]x=4 \implies y=\dfrac{1}{2}(4)-5 \implies (4,-3)[/tex]
Inequality 2
[tex]x+y\leq -3[/tex]
[tex]\implies y\leq -x-3[/tex]
[tex]x=0\implies y=-(0)-3\implies (0,-3)[/tex]
[tex]x=4\implies y=-(4)-3\implies (4,-7)[/tex]
When graphing inequalities
< or > : dashed line
≤ or ≥ : solid line
< or ≤ : shade below the line
> or ≥ : shade above the line
Therefore,
Inequality 1: plot points (0, -5) and (4, -3) and draw a solid line through them.
Inequality 2: plot points (0, -3) and (4, -7) and draw a solid line through them.
Shade the area below both lines from where the lines intersect.
