The value of x that gives the box the greatest volume is approximately 2.08
How to determine the value that gives the greatest volume?
The equation of the volume of the box is given as:
V(x) = x(12 - 2x)(13 - 2x)
Expand
V(x) = (12x - 2x^2)(13 - 2x)
V(x) = 156x - 24x^2 - 26x^2 + 4x^3
V(x) = 156x - 50x^2 + 4x^3
Differentiate the function
V'(x) = 156 - 100x + 12x^2
Set to 0
156 - 100x + 12x^2 = 0
Rewrite as:
12x^2 - 100x + 156 =0
Divide through by 4
3x^2 - 25x + 39 =0
Using a graphing calculator, the values of x are:
x = 2.08 and x = 6.26
Substitute these values of x in V(x)
V(2.08) = 2.08 * (12 - 2 * 2.08)(13 - 2 * 2.08) = 144.16
V(6.26) = 6.26 * (12 - 2 * 6.26)(13 - 2 * 6.26) = -1.56
The volume cannot be negative.
So, we have:
V(2.08) = 144.16
Hence, the value of x that gives the box the greatest volume is approximately 2.08
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