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A 10.00 g sample of wood from an archaeological site produced 3072 counts in a 10-hour measurement owing to the presence of carbon-14, while a 10.00 g sample of new wood produced 9216 counts in the same period of time. The half-life of carbon-14 is 5730 years. How old is the wood from the archaeological site

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pstnonsonjoku

From the calculation, the age of the sample of carbon - 14 is 9156 years.

What is radioactivity?

The term radioactivity refers to the fact that a substance could disintegrate spontaneously when left alone.

Now, given that;

0.693/t1/2 = 2.303/t log (No/N)

t1/2 = half life

t = age of the sample

No = amount of sample originally present

N = amount of sample present at time t

Hence;

0.693/5730 =  2.303/t  log (9216/3072)

1.2 * 10^-4 =  2.303/t * 0.4771

1.2 * 10^-4 = 1.09876/t

t =  1.09876/1.2 * 10^-4

t = 9156 years

Learn more about carbon-14:https://brainly.com/question/4206267

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