In this question, we are presented with two triangles are required to find he missing sides in them. the missing side in the first triangle is equal to 8 and the missing sides in the second triangle are 8.660, 5 and 60 for the adjacent, opposite and the second angle respectively
Trigonometric Ratio
In the first triangle, we need to use trigonometric ratio to find the missing side in the triangle
Data;
- Angle = 45
- hypothenuse = [tex]8\sqrt{2}[/tex]
- adjacent = x
To find the adjacent side, we need to use cosine rule on this problem.
[tex]cos\theta = \frac{adjacent}{hypothenuse} \\cos45 = \frac{x}{8\sqrt{2} } \\x = 8[/tex]
The adjacent side is equal to 8 units
In the second triangle, we also need to use trigonometric ratio, but let's write down our data
- angle = 30
- hypothenuse = 10
- opposite = ?
- adjacent = ?
We can use both cosine and sine rule here or use one and use Pythagoras's theorem to find the other side.
[tex]cos \theta = \frac{adjacent}{hypothenuse} \\cos 30 = \frac{x}{10} \\x = 8.660[/tex]
The adjacent side is equal to 8.660, let's find the opposite side using sine rule
[tex]sin\theta = \frac{opposite}{hypothenuse} \\sin 30 = \frac{y}{10} \\y = 5[/tex]
And lastly, the value of the other angle is
[tex]90 + 30 + z = 180\\z = 180 - 120\\\\z = 60[/tex]
From the calculations above, the missing side in the first triangle is equal to 8 and the missing sides in the second triangle are 8.660, 5 and 60 for the adjacent, opposite and the second angle respectively
Learn more on trigonometric ratios here;
https://brainly.com/question/11967894
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