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Find the amount of sheet metal needed to form a conical funnel of base radius 30 cm and vertical height 50 cm, allowing for a 0.5 cm overlap at the join

Respuesta :

MrRoyal

The amount of sheet metal needed to form the conical funnel is 5525 cm²

How to determine the amount of sheet?

The given parameters are:

  • Radius, r = 30 cm
  • Vertical height, h = 50 cm
  • Overlap = 0.5 cm

Start by calculating the slant height (l) of the cone using:

l = √(r² + h²)

This gives

l = √(30² + 50²)

Evaluate

l = 58.31

The lateral surface area of the conical funnel including the overlap is then calculated as:

A = πrl + Overlap * l

This gives

A = 3.142 * 30 * 58.31 + 0.5 * 58.31

Evaluate

A = 5525.4556

Approximate

A = 5525

Hence. the amount of sheet metal needed is 5525 cm²

Read more about surface areas at:

https://brainly.com/question/6613758

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