A marathon swim follows a triangular course marked with three buoys, A, B, and C. The distance from buoy A to B is 400 meters, B to C is 500 meters, and C to A is 600 meters. What is the smallest angle the swimmers must turn between the buoys

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By applying the law of cosine, the smallest angle which the swimmers must turn between the buoys is 41.4°.

How to determine the smallest angle?

In order to determine the smallest angle which the swimmers must turn between the buoys, we would apply the law of cosine.

Given the following data:

  • Side AB = c = 400 meters.
  • Side BC = a = 500 meters.
  • Side CA = b = 600 meters.

Form the law of cosine, we have:

[tex]CosC =\frac{a^2 + b^2 - c^2}{2ab} \\\\CosC =\frac{500^2 + 600^2 - 400^2}{2 \times 500 \times 600}\\\\CosC =\frac{450000}{600000}\\\\C = cos^{-1} 0.75\\\\[/tex]

C = 41.4°.

For angle B, we have:

[tex]CosB =\frac{a^2 + c^2 - b^2}{2ac} \\\\CosB =\frac{500^2 + 400^2 - 600^2}{2 \times 500 \times 400}\\\\CosB =\frac{1}{8}\\\\B = cos^{-1} 0.125\\\\[/tex]

B = 82.8°.

For angle A, we have:

[tex]CosA =\frac{b^2 + c^2 - a^2}{2bc} \\\\CosA =\frac{600^2 + 400^2 - 500^2}{2 \times 600 \times 400}\\\\CosA =\frac{9}{16}\\\\A = cos^{-1} 0.5625\\\\[/tex]

A = 55.8°.

Read more on law of cosine here: https://brainly.com/question/27613782

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