Answer:
0.8976 seconds
Explanation:
The period of oscillation for the simple harmonic motion can be found using the formula ...
T = 2π√(d/g)
where d is the displacement of the spring due to the attached weight, and g is the acceleration due to gravity.
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For d = 0.20 meters, the period is ...
T = 2π√(0.20/9.8) ≈ 0.8976 . . . . seconds
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Additional comment
The formula for the oscillator period is usually seen as ...
T = 2π√(m/k)
where m is the mass in the system and k is the spring constant. The value of the spring constant is calculated from ...
k = mg/d
Using that in the formula, we find it simplifies to ...
[tex]T=2\pi\sqrt{\dfrac{m}{k}}=2\pi\sqrt{\dfrac{m}{\left(\dfrac{mg}{d}\right)}}=2\pi\sqrt{\dfrac{d}{g}}[/tex]
