willowtree237
contestada

What quantity in moles of K₂S will be required to
completely react with 50.0 mL of 0.200 M FeCl3?
3 K₂S(aq) + 2 FeCl3(aq) → Fe₂S³(s) + 6 KCl(aq)

Respuesta :

Medunno13

Answer: 0.105 mol

Explanation:

Using the molarity formula,

  • 0.200 = (moles of potassium sulfide)/(0.05)
  • moles of potassium sulfide = 0.01 mol

From the coefficients of the equation, we know that for every 3 moles of potassium sulfide consumed, 2 moles of iron(III) chloride are consumed.

This means that if 0.01 moles of iron(III) chloride are consumed, 0.0150 mol (to 3 sf) of potassium sulfide will be consumed.

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