contestada

A 10.0 kg monkey swings on a vine from a point which is 40.0m above the jungle
floor to a point which is 15.0m above the floor.

a. How much has the monkey’s speed
increased when he reaches the 15.0m point?

b. If the monkey was moving at 2.00 m/s initially, what will be his speed at the 15.0m point?

Respuesta :

The monkey was moving at 2.00 m/s initially, his speed at the 15.0m point will be 22.2m/s.

What is speed?

Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while V for the final speed. its si unit is m/sec.

Given data;

Mass of monkey ,m = 10kg

Height,h = 25m

initial velocity,u= 2m/s

From Newton's third equation of motion;

v²  = u²  + 2gh

v²   = 2² + (2 x 9.8 x 25 )

v²= 494 m²/sec²

v = 22.2m/s

The monkey was moving at 2.00 m/s initially,

Hence, his speed at the 15.0m point will be 22.2m/s.

To learn more about the speed refer to the link;

https://brainly.com/question/7359669

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