The velocity =3.015 m/s and the tension on each end of the chord is 62.5 N.
There are three laws of motion upon which the basics of mechanics is based , It relates the motion of the object to the force acting on it .
Acceleration of two systems = a
a =(total force) / total mass
The force on the first object , A works downward and the force on the second block , B works upward direction.
Therefore ,
[tex]\rm a = \dfrac{(w_ag - m_b)g}{m_a+m_b}[/tex]
mass of the first object = 10.4 kg and
mass of second object = 4.6 kg
gravitational acceleration = 9.81 m/sq.sec
Acceleration is given b y
a = { (10.4 -4.6) *9.8}/{10.4+4.6}
a = 3.79 m/sq.second
Initial Velocity = 0
Final Velocity = v
Displacement = 1.2m
acceleration = 3.79 m/sq.second
v² = u² + 2as
v² = 0 + 2* 3.79 * 1.2
v = 3.015 m/s
For calculating The tension on each end of the chord
[tex]\rm T = m_a g - m_a * a[/tex]
T = 10.4(9.8-3.79) = 62.5 N
Therefore the tension on each end of the chord is 62.5 N.
To know more about Laws of motion
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