Two objects a and b with masses 10.4 kg and 4.6 kg respectively attached to two ends of a light cord that passes a very light, fixed pulley. the system is released from rest so that a and b move vertically.
a/ use the energy consideration to find the velocity of a and b after they have moved 1.2 m.
b/ compute the tension on each end of the cord.

Respuesta :

The velocity =3.015 m/s and the tension on each end of the chord is 62.5 N.

What are Newton's Law of motion ?

There are three laws of motion upon which the basics of mechanics is based , It relates the motion of the object to the force acting on it .

Acceleration of two systems = a

a =(total force) / total mass

The force on the first object , A  works downward and the force on the second block , B  works upward direction.

Therefore ,

[tex]\rm a = \dfrac{(w_ag - m_b)g}{m_a+m_b}[/tex]

mass of the first object = 10.4 kg and

mass of second object = 4.6 kg

gravitational acceleration = 9.81 m/sq.sec

Acceleration is given b y

a = { (10.4 -4.6) *9.8}/{10.4+4.6}

a = 3.79 m/sq.second

Initial Velocity = 0

Final Velocity = v

Displacement = 1.2m

acceleration = 3.79 m/sq.second

v² = u² + 2as

v² = 0 + 2* 3.79 * 1.2

v = 3.015 m/s

For calculating The tension on each end of the chord

[tex]\rm T = m_a g - m_a * a[/tex]

T = 10.4(9.8-3.79) = 62.5 N

Therefore the tension on each end of the chord is 62.5 N.

To know more about Laws of motion

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