A car of mass 1000 kg is heading east at 25 m/s. it collides with a car of mass 1200 kg heading north at 30 m/s. when the cars collide, they stick together.

a. what is the total momentum of the system before the collision? remember that momentum is a vector quantity, and write the momentum in component notation, with x and y unit vectors. (1 point)

b. what is the total momentum of the system after the collision? write the momentum in component notation, with x and y unit vectors. (1 point)

c. what is the velocity of the cars after the collision? write the velocity in component notation, with x and y unit vectors. (1 point)

d. at what angle do the cars move after the collision? (1 point)

Momentum is the property of a moving body that the body has by virtue of its mass and motion and that is equal to the product of the body's mass and velocity.

Given,

[tex]M_{1}[/tex]= 1000 kg , [tex]M_{2}[/tex] = 1200Kg

[tex]V_{1}[/tex]= 25 m/s , [tex]V_{2}[/tex] = 30 m/s

a. What is the total momentum of the system before the collision?

The total momentum of the system before collision :

[tex]P(_{xy} ) = P_{x} + P_{y}[/tex]

[tex]P_{x} = 1000*25= 25000 kgm/s \\\\P_{y} = 1200*30 = 3600 kgm/s\\[/tex]

25000kgm/s + (-3600 kgm/s) = 21,400 kgm/s

b. What is the total momentum of the system after the collision?

[tex]P(_{xy} ) = P_{x} + P_{y}[/tex]

25000kgm/s + 3600 kgm/s =28,600 kgm/s

d. at what angle do the cars move after the collision?

From Triangle law of vector addition ,

the resultant of both vectors will be given by third side of the triangle taken in opposite direction.

So , if the resultant velocity makes an angle . Then ,

tan θ =[tex]\frac{v_{2} }{v_{1} }[/tex]

Substituting the respective values,

tanθ = [tex]\frac{30}{25}[/tex]

Simplify ,

tan θ = [tex]\frac{6}{5}[/tex]

θ = [tex]tan^{-1} (\frac{6}{5} )[/tex]

Hence the cars move at an angle of tan-¹(6/5) NE after the collision .

Learn more about momentum here:

https://brainly.com/question/24030570

#SPJ1