The radius of the circumscribed circle and m∠OAC will be 6.5 cm and 44.8°.
The complete question and missing diagram is given below.
Suppose AC = 5 cm, BC = 12 cm, and mAC = 45.2°. to the nearest tenth of a unit, the radius of the circumscribed circle is cm and m∠OAC.
It is the center of an equidistant point drawn from the center. The radius of a circle is the distance between the center and the circumference.
Suppose AC = 5 cm, BC = 12 cm, and mAC = 45.2°.
Then the radius of the circumscribed circle will be given by Pythagoras theorem.
(2r)² = 5² + 12²
(2r)² = 169
(2r) = 13
r = 6.5 cm
The angle subtend by7 the end points of the diameter at periphery is 90 degrees.
And the measure of the angle ∠OAC will be
∠OAC + 90° + 45.2° = 180°
∠OAC = 44.8°
More about the circle link is given below.
https://brainly.com/question/11833983
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