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In an isolated population of 10,000 rabbits, 900 are homozygous for a recessive mutant Sp1 allele. Assuming the population is in Hardy-Weinberg equilibrium, what is the percentage of rabbits in the population that would be heterozygous for the mutant Sp1 allele

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42% of rabbits in the population are heterozygous for the mutant Sp1 allele

Hardy-Weinberg equilibrium

  • Assume that p is the frequency of the dominant allele
  • p² is the frequency of the organisms with homozygous dominant genotype
  • Assume that q is the frequency of the recessive allele
  • q² is the frequency of the organisms with homozygous recessive genotype
  • 2pq is the frequency of the organisms with heterozygous genotype
  • p+q = 1

According to the question, 900 out of 10000 rabbits are homozygous recessive

  • This implies that q² = 900/10000= 9/100= 0.09
  • So, q = 0.3
  • The frequency of the recessive allele is 0.3
  • p = 1-q = 1-0.3= 0.7

For organisms with heterogenous genotype, their frequency is 2pq

2pq= 2 x 0.3 x 0.7 = 0.42

In terms of percentage, 0.42x 100% = 42%

Therefore, 42% of rabbits in the population are heterozygous for the mutant Sp1 allele.

Learn more about Hardy-Weinberg equilibrium here:

https://brainly.com/question/10482905

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