Respuesta :
9-fluorenone is a limiting reagent and theoretical yield.
What is 9-fluorenol?
Fluoren-9-ol is a member of the class of hydroxyfluorenes that is 9H-fluorene substituted by a hydroxy group at position 9.
Inspect stoichiometry of the given reaction as per the balanced equation below:
[tex]4C_{13}H_8O + NaBH_4 + 4CH_3 OH[/tex] → [tex]4C _{13} H _{10} O + NaB(OCH_3 )_4[/tex]
Given weight:
0.6 grams methanol
0.05 grams 9-fluorenol
0.792 [tex]NaBH_4[/tex]
Out of the three reactants, [tex]NaBH_4[/tex] acts as a reducing agent only and hence the reaction can occur only when [tex]NaBH_4[/tex] is present in relatively much smaller amounts. But the yield of the product,9-fluorenol, is not governed by its quantity.
Theoretically, when equimolar amounts of reactants ( 9-fluorenone and methanol ) are taken for reaction in presence of [tex]NaBH_4[/tex] an equivalent quantity of product, 9- fluorine is obtained, as inspected in the above stoichiometric relations. But practically we have used a lesser number of moles of 9-fluorenone than theoretically needed, hence in this case it should serve as the limiting reagent.
9- fluorenone, methanol & [tex]NaBH_4[/tex] are the reactants, while the product 9-fluorenol would be obtained = 0.0033 moles
This would represent the theoretical yield of the product 9-fluorenone, as we have used an excess of methanol thus facilitating the reaction to go to completion.
Hence, 9-fluorenone is a limiting reagent.
Learn more about the 9-fluorenol here:
https://brainly.com/question/6798923
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