The value of x in the second matrix is -1
How to determine the value of x?
The operation is given as:
[tex]\left[\begin{array}{ccc}2&-1&1\\1&1&1\\4&-2&2\end{array}\right] \left[\begin{array}{c}4&11&5\end{array}\right] \to \left[\begin{array}{ccc}0&-3&x\\1&1&1\\4&-2&2\end{array}\right] \left[\begin{array}{c}-18&11&5\end{array}\right][/tex]
Let the rows be represented by R1, R2 and R3.
By observation, the row operation performed is:
[tex]R1 \to R1 - 2R2[/tex]
This means that:
The new elements of row 1 are gotten by subtracting twice the elements of row 2 from row 1.
Using the above operation, we have:
x = 1 - 2 * 1
Evaluate the difference
x = -1
Hence, the value of x is -1
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