Respuesta :
The difference of the polynomials is [tex]1.3t^{3}-0.2t^{2}-6t-8[/tex] and the additive inverse of the polynomial being subtracted is [tex]-0.6t^{2} +8+18t[/tex].
The given polynomials are [tex](1.3t^{3}+0.4t^{2} -24t )[/tex] and [tex]0.6t^{2} +8-18t[/tex].
We need to find the additive inverse of the polynomial being subtracted.
What is additive inverse?
In mathematics, the additive inverse of a number a is the number that, when added to a yields zero. This number is also known as the opposite, sign change, and negation.
Now, [tex](1.3t^{3}+0.4t^{2} -24t )-(0.6t^{2} +8-18t)[/tex]
[tex]=1.3t^{3}+0.4t^{2}-0.6t^{2}-24t+18t-8[/tex]
[tex]=1.3t^{3}-0.2t^{2}-6t-8[/tex]
The additive inverse of the polynomial being subtracted is [tex]-0.6t^{2} +8+18t[/tex].
Therefore, the difference of the polynomials is [tex]1.3t^{3}-0.2t^{2}-6t-8[/tex] and the additive inverse of the polynomial being subtracted is [tex]-0.6t^{2} +8+18t[/tex].
To learn more about the additive inverse visit:
https://brainly.com/question/13715269.
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