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Using the balanced chemical equation, determine the
number of moles of aluminum required to react with 7.53
mol of chlorine.

2Al(s) + 3Cl2(g) -> 2AlCl3(s)

Respuesta :

nkosimlungisi908

Answer:

5.02 mol

Explanation:

n(Al) : n(Cl)

2 : 3

x : 7.53

3x = 15.06

n(Al) = 5.02mol

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